看到一个kad技术的资料求解

没有讲为什么是0……引用里有一篇官网的讨论，但也没有讲清楚 当然 也可能是我没看到，求链接指引

那个其实是移位，*256是二进制左移八位 那个计算的结果就是把ip最后一部分放到最高位 16777216 是 00000001 00000000 00000000 00000000 所以只要ip最后一部分(二进制8位)不为零就一定比它大，跟其他无关 [ 本帖最后由 10293817 于 2010-4-22 13:51 编辑 ]

对，这里说的其实是ed2k协议

google搜到的 http://sourceforge.net/projects/ ... ocol-0.6.2/download 非官方…… ---- 内外网这个，内网用户之间不能直连 我不明白的是为什么ip最后一位为0可以作为判别内外网的标准 ---- wikipedia Users who cannot be reached from the outside because they are firewalled, behind a NAT device that has not been correctly port forwarded or their IP address ends with a zero (e.g. 123.45.67.0)[3] get a "Low ID" from the servers. They are still able to upload and download but need the help of servers or other kad clients to be reached by other clients. Since they cannot be notified that they are in front of an upload queue, they have to poll peers if an upload slot is available. Since they cannot connect to any other Low ID clients, they see only 40%-60% [4] of the clients that a High ID can see. Their IP/ports are not exchanged between other peers, limiting their possibilities for finding sources via eMule's pure-P2P source exchange. NAT这个可以理解，内网用户可能没有固定的公网IP和端口 但是0是什么意思…… [ 本帖最后由 10293817 于 2010-4-22 12:52 编辑 ]

貌似不是“例如”唉 5.1. HighID and LowID ------------------------- The <Client ID> match the client IP address in case of high ID, so if the ID value is stored in hexadecimal as 0xAABBCCDD, the IP is DD.CC.BB.AA. The <Client ID> is a low ID when it is below 16777216, so the last low ID is 0x00FFFFFF, every IP that end with a 0 is considered as a low ID. 我倒是搞不懂了…… 为啥要用最后一位是0来判断……和内网外网又有什么关系……

(本人小白) a + b << 8 + c << 16 + d << 24 我怎么觉得好像倒了…… 按这个说法，就是ip最后一部分(二进制8位)不能是0，这个……对吗…… -- 如果反过来的话：a << 24 + b << 16 + c << 8 + d 那就是32位的ip地址 网络设备内，ip就是这种形式 a.b.c.d其实是方便人看的表示方法